(6x-2)^2+4=20

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Solution for (6x-2)^2+4=20 equation: 



(6x-2)^2+4=20

We move all terms to the left:

(6x-2)^2+4-(20)=0

We add all the numbers together, and all the variables

(6x-2)^2-16=0

We move all terms containing x to the left, all other terms to the right

(6x-2)^2=16

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